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48x^2-86x+35=0
a = 48; b = -86; c = +35;
Δ = b2-4ac
Δ = -862-4·48·35
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-86)-26}{2*48}=\frac{60}{96} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-86)+26}{2*48}=\frac{112}{96} =1+1/6 $
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